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2.4 KiB
title: JavaScript · 十进制数转二进制 summary: 用JavaScript将十进制数转二进制数 created 2022-03-04T14:57:48.683Z draft: '' tags:
- JavaScript categories:
- JavaScript lastmod: 2022-04-16T12:54:16.167Z type: default
changelogs:
- tag: "20220308"
summary:
- 将push
改为unshift
- 使用padding
填充字符串
- 修改binNumber.length >= binBit
题目
Task1
实现当点击转化按钮时,将输入的十进制数字转化为二进制,并显示在 result
的 p
标签内
Task2
- 转化显示后的二进制数为 bin-bit 中输入的数字宽度,例如
dec-number
为 5 ,bin-bit
为 5 ,则转化后数字为00101
- 如果
bin-bit
小于转化后的二进制本身位数,则使用原本的位数,如dec-number
为 5 ,bin-bit
为 2 ,依然输出101
,但同时在 console 中报个错。
解法
<input id="dec-number" type="number" placeholder="输入一个十进制非负整数" />
<input id="bin-bit" type="number" placeholder="输入转化后二进制数字位数" />
<button id="trans-btn">转化为二进制</button>
<p id="result">运算结果</p>
<script>
/////// Task 1
const btn = document.querySelector('#trans-btn')
const result = document.querySelector('#result')
function dec2bin() {
let decNumber = Number(document.querySelector('#dec-number').value)
// 判断输入必须为一个非负整数
if (decNumber < 0 || !Number.isInteger(decNumber)) {
alert('请输入一个非负整数!')
}
// 求余
let bin = []
let remainder
while (decNumber !== 0) {
remainder = decNumber % 2
decNumber = parseInt(decNumber / 2)
bin.unshift(remainder)
}
let binNumber = bin.join('')
////// Task2
let binBit = Number(document.querySelector('#bin-bit').value)
if (binNumber.length >= binBit) {
binNumber = binNumber.slice(0, binBit + 1)
} else {
binNumber = binNumber.padStart(binBit, '0')
}
result.innerHTML = `运算结果:${binNumber}`
}
btn.addEventListener('click', dec2bin)
</script>